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By Gustave P. Corten

This seems to be a doctoral thesis on strength extraction from wind generators. The contents are in English with a few peripheral dutch language.

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The lift force will be balanced by the change of momentum of the mass flow per unit span. 2). The resulting velocity change will be ∆U=L/ m . The kinetic power of the inflow was ½ m U2 and decreased to ½ m (U-∆U)2 when passing the airfoil. Thus the kinetic power extracted from the flow per unit span Pflow is: Pflow = m U∆U − m (∆U ) 2 L2 . 27) The expression on the right hand side follows after a substitution of ∆U by L/ m . So, the power extracted by the lift force U·L exceeds the power extracted from the flow by L2/(2 m ).

In fact, when the partial derivative is estimated inside the dead-water region, we find ∂vr/(r∂θ) ≈ 0. One might come up with the statement that the order of the partial derivatives in the deadwater region is still equal to that in the attached region, although the magnitudes are very different. However to reduce the Navier-Stokes equations we assume that the smaller terms can be neglected. The order of a term is not only decisive for its magnitude, the coefficient is also important. Snel’s analysis is based on orders only.

19 Flow Separation on Wind Turbine Blades Thus the power extracted from the flow in this initial situation is L·U, which has to be compared with 0 for Prandtl's finite airfoil. The lift force will be balanced by the change of momentum of the mass flow per unit span. 2). The resulting velocity change will be ∆U=L/ m . The kinetic power of the inflow was ½ m U2 and decreased to ½ m (U-∆U)2 when passing the airfoil. Thus the kinetic power extracted from the flow per unit span Pflow is: Pflow = m U∆U − m (∆U ) 2 L2 .

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